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Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters Formula

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Temperature given RP is the degree or intensity of heat present in a substance or object. Check FAQs

T RP = ({(\frac{a \cdot 64 \cdot (\frac{p}{P r})}{27 \cdot ({[R]}^{2})})}^{\frac{1}{3}}) \cdot T r

T_RP - Temperature given RP?a - Clausius Parameter a?p - Pressure?P_r - Reduced Pressure?T_r - Reduced Temperature?[R] - Universal gas constant?

Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters Example

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Here is how the Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters equation looks like with Values.

Here is how the Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters equation looks like with Units.

Here is how the Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters equation looks like.

15.0793 = ({(\frac{0.1 \cdot 64 \cdot (\frac{800}{0.8})}{27 \cdot ({8.3145}^{2})})}^{\frac{1}{3}}) \cdot 10

15.0793K = ({(\frac{0.1 \cdot 64 \cdot (\frac{800Pa}{0.8})}{27 \cdot ({8.3145}^{2})})}^{\frac{1}{3}}) \cdot 10

15.0793 = ({(\frac{0.1 \cdot 64 \cdot (\frac{800}{0.8})}{27 \cdot ({8.3145}^{2})})}^{\frac{1}{3}}) \cdot 10

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Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters Solution

Follow our step by step solution on how to calculate Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters?

FIRST Step Consider the formula

T RP = ({(\frac{a \cdot 64 \cdot (\frac{p}{P r})}{27 \cdot ({[R]}^{2})})}^{\frac{1}{3}}) \cdot T r

Next Step Substitute values of Variables

∴

T RP = ({(\frac{0.1 \cdot 64 \cdot (\frac{800Pa}{0.8})}{27 \cdot ({[R]}^{2})})}^{\frac{1}{3}}) \cdot 10

Next Step Substitute values of Constants

∴

T RP = ({(\frac{0.1 \cdot 64 \cdot (\frac{800Pa}{0.8})}{27 \cdot ({8.3145}^{2})})}^{\frac{1}{3}}) \cdot 10

Next Step Prepare to Evaluate

∴

T RP = ({(\frac{0.1 \cdot 64 \cdot (\frac{800}{0.8})}{27 \cdot ({8.3145}^{2})})}^{\frac{1}{3}}) \cdot 10

Next Step Evaluate

∴

T RP = 15.0793497115397K

LAST Step Rounding Answer

∴

T RP = 15.0793K

Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters Formula Elements

Variables

Constants

Temperature given RP

Temperature given RP is the degree or intensity of heat present in a substance or object.

Symbol: T_RP

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Temperature given RP

Clausius Parameter a

Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

Symbol: a

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Clausius Parameter a

Pressure

Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.

Symbol: p

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Pressure

Reduced Pressure

Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless.

Symbol: P_r

Measurement: NAUnit: Unitless

Note: Value should be between 0 to 1.

Formulas to find Reduced Pressure

Reduced Temperature

Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.

Symbol: T_r

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Reduced Temperature

Universal gas constant

Universal gas constant is a fundamental physical constant that appears in the ideal gas law, relating the pressure, volume, and temperature of an ideal gas.

Symbol: [R]

Value: 8.31446261815324

Other formulas in Actual Temperature of Real Gas category

Go Actual Pressure of Real Gas given Clausius Parameter a, Reduced and Critical Parameters

Pa = (\frac{27 \cdot ({[R]}^{2}) \cdot ({T' c}^{3})}{64 \cdot a}) \cdot P r

Go Actual Pressure of Real Gas given Clausius Parameter b, Reduced and Actual Parameters

Pb = (\frac{[R] \cdot (\frac{T rg}{T r})}{4 \cdot ((\frac{V real}{V r}) - b')}) \cdot P r

Go Actual Pressure of Real Gas given Clausius Parameter c, Reduced and Actual Parameters

Pc = (\frac{3 \cdot [R] \cdot (\frac{T rg}{T r})}{8 \cdot (c + (\frac{V real}{V r}))}) \cdot P r

Go Actual Temperature of Real Gas using Critical and Reduced Temperature

T RT = T r \cdot T' c

How to Evaluate Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters?

Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters evaluator uses Temperature given RP = (((Clausius Parameter a*64*(Pressure/Reduced Pressure))/(27*([R]^2)))^(1/3))*Reduced Temperature to evaluate the Temperature given RP, The Actual Temperature of real gas given Clausius parameter a, reduced and actual parameters formula is defined as the degree or intensity of heat present in the volume of real gas. Temperature given RP is denoted by T_RP symbol.

How to evaluate Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters using this online evaluator? To use this online evaluator for Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters, enter Clausius Parameter a (a), Pressure (p), Reduced Pressure (P_r) & Reduced Temperature (T_r) and hit the calculate button.

FAQs on Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters

What is the formula to find Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters?

The formula of Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters is expressed as Temperature given RP = (((Clausius Parameter a*64*(Pressure/Reduced Pressure))/(27*([R]^2)))^(1/3))*Reduced Temperature. Here is an example- 2.201585 = (((0.1*64*(800/0.8))/(27*([R]^2)))^(1/3))*10.

How to calculate Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters?

With Clausius Parameter a (a), Pressure (p), Reduced Pressure (P_r) & Reduced Temperature (T_r) we can find Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters using the formula - Temperature given RP = (((Clausius Parameter a*64*(Pressure/Reduced Pressure))/(27*([R]^2)))^(1/3))*Reduced Temperature. This formula also uses Universal gas constant .

Can the Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters be negative?

Yes, the Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters, measured in Temperature can be negative.

Which unit is used to measure Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters?

Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters is usually measured using the Kelvin[K] for Temperature. Celsius[K], Fahrenheit[K], Rankine[K] are the few other units in which Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters can be measured.

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Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters Formula

Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters Example

Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters Solution

Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters Formula Elements

Other formulas in Actual Temperature of Real Gas category

How to Evaluate Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters?

FAQs on Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters

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