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Activation Energy given Slope of Line between Log K and Temp Inverse Formula

GoActivation Energy given Slope of Line between LnK and Temperature Inverse Formula

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Activation Energy is the minimum amount of energy that is required to activate atoms or molecules to a condition in which they can undergo chemical transformation. Check FAQs

E a = - 2.303 \cdot [R] \cdot m

E_a - Activation Energy?m - Slope of Line Between Log K and 1/T?[R] - Universal gas constant?

Activation Energy given Slope of Line between Log K and Temp Inverse Example

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Here is how the Activation Energy given Slope of Line between Log K and Temp Inverse equation looks like with Values.

Here is how the Activation Energy given Slope of Line between Log K and Temp Inverse equation looks like with Units.

Here is how the Activation Energy given Slope of Line between Log K and Temp Inverse equation looks like.

6606.1316 = - 2.303 \cdot 8.3145 \cdot -345

6606.1316J/mol = - 2.303 \cdot 8.3145 \cdot -345K

6606.1316 = - 2.303 \cdot 8.3145 \cdot -345

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Temperature Coefficient » fx Activation Energy given Slope of Line between Log K and Temp Inverse

Activation Energy given Slope of Line between Log K and Temp Inverse Solution

Follow our step by step solution on how to calculate Activation Energy given Slope of Line between Log K and Temp Inverse?

FIRST Step Consider the formula

E a = - 2.303 \cdot [R] \cdot m

Next Step Substitute values of Variables

∴

E a = - 2.303 \cdot [R] \cdot -345K

Next Step Substitute values of Constants

∴

E a = - 2.303 \cdot 8.3145 \cdot -345K

Next Step Prepare to Evaluate

∴

E a = - 2.303 \cdot 8.3145 \cdot -345

Next Step Evaluate

∴

E a = 6606.13155631438J/mol

LAST Step Rounding Answer

∴

E a = 6606.1316J/mol

Activation Energy given Slope of Line between Log K and Temp Inverse Formula Elements

Variables

Constants

Activation Energy

Activation Energy is the minimum amount of energy that is required to activate atoms or molecules to a condition in which they can undergo chemical transformation.

Symbol: E_a

Measurement: Energy Per MoleUnit: J/mol

Note: Value can be positive or negative.

Formulas to find Activation Energy

Slope of Line Between Log K and 1/T

Slope of line Between Log K and 1/T is defined as the graph between logk versus 1/T is a straight line. The graph between logk versus 1/T is a straight line.

Symbol: m

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Slope of Line Between Log K and 1/T

Universal gas constant

Universal gas constant is a fundamental physical constant that appears in the ideal gas law, relating the pressure, volume, and temperature of an ideal gas.

Symbol: [R]

Value: 8.31446261815324

Other Formulas to find Activation Energy

Go Activation Energy given Slope of Line between LnK and Temperature Inverse

E a = - (m slope \cdot [R])

Other formulas in Temperature Coefficient category

Go Temperature Coefficient using Rate Constant

Φ = \frac{K (t+10)°C}{K (t°c)}

Go Rate Constant at Temperature 2

K 2 = ((K 1) \cdot {(Φ)}^{\frac{T 2 - T 1}{10}})

Go Fraction of Total No. of Molecules Undergoing Chemical Reaction

e -Ea/RT = (\frac{k}{A})

Go Temperature Coefficient using Activation Energy

Φ = e^{H Activation \cdot ((\frac{1}{T 1}) - (\frac{1}{T 2}))}

How to Evaluate Activation Energy given Slope of Line between Log K and Temp Inverse?

Activation Energy given Slope of Line between Log K and Temp Inverse evaluator uses Activation Energy = -2.303*[R]*Slope of Line Between Log K and 1/T to evaluate the Activation Energy, Activation Energy given Slope of Line between Log K and Temp Inverse has defined that the graph between LogK versus 1/T is a straight line. The plot between Log K vs 1/T will give slope −Ea/2.303R. Activation Energy is denoted by E_a symbol.

How to evaluate Activation Energy given Slope of Line between Log K and Temp Inverse using this online evaluator? To use this online evaluator for Activation Energy given Slope of Line between Log K and Temp Inverse, enter Slope of Line Between Log K and 1/T (m) and hit the calculate button.

FAQs on Activation Energy given Slope of Line between Log K and Temp Inverse

What is the formula to find Activation Energy given Slope of Line between Log K and Temp Inverse?

The formula of Activation Energy given Slope of Line between Log K and Temp Inverse is expressed as Activation Energy = -2.303*[R]*Slope of Line Between Log K and 1/T. Here is an example- 6606.132 = -2.303*[R]*(-345).

How to calculate Activation Energy given Slope of Line between Log K and Temp Inverse?

With Slope of Line Between Log K and 1/T (m) we can find Activation Energy given Slope of Line between Log K and Temp Inverse using the formula - Activation Energy = -2.303*[R]*Slope of Line Between Log K and 1/T. This formula also uses Universal gas constant .

What are the other ways to Calculate Activation Energy?

Here are the different ways to Calculate Activation Energy-

Activation Energy=-(Slope of Line B/w Ln K and 1/T*[R])

Can the Activation Energy given Slope of Line between Log K and Temp Inverse be negative?

Yes, the Activation Energy given Slope of Line between Log K and Temp Inverse, measured in Energy Per Mole can be negative.

Which unit is used to measure Activation Energy given Slope of Line between Log K and Temp Inverse?

Activation Energy given Slope of Line between Log K and Temp Inverse is usually measured using the Joule Per Mole[J/mol] for Energy Per Mole. KiloJoule Per Mole[J/mol], Kilocalorie Per Mole[J/mol] are the few other units in which Activation Energy given Slope of Line between Log K and Temp Inverse can be measured.

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