FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

A-Phase Current using A-Phase Voltage(LGF) Formula

GoA-Phase Current using Positive Sequence Current (LGF) Formula

GoA-Phase Current using Negative Sequence Current (LGF) Formula

Fx Copy

LaTeX Copy

A-phase Current LG is the current that flows into the a-phase in open conductor fault. Check FAQs

I a(lg) = \frac{V a(lg)}{Z f(lg)}

I_a(lg) - A-Phase Current LG?V_a(lg) - A Phase Voltage LG?Z_f(lg) - Fault Impedance LG?

A-Phase Current using A-Phase Voltage(LGF) Example

With values

With units

Only example

Here is how the A-Phase Current using A-Phase Voltage(LGF) equation looks like with Values.

Here is how the A-Phase Current using A-Phase Voltage(LGF) equation looks like with Units.

Here is how the A-Phase Current using A-Phase Voltage(LGF) equation looks like.

7.9667 = \frac{11.95}{1.5}

7.9667A = \frac{11.95V}{1.5Ω}

7.9667 = \frac{11.95}{1.5}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Electrical » Category

Power System » fx A-Phase Current using A-Phase Voltage(LGF)

A-Phase Current using A-Phase Voltage(LGF) Solution

Follow our step by step solution on how to calculate A-Phase Current using A-Phase Voltage(LGF)?

FIRST Step Consider the formula

I a(lg) = \frac{V a(lg)}{Z f(lg)}

Next Step Substitute values of Variables

∴

I a(lg) = \frac{11.95V}{1.5Ω}

Next Step Prepare to Evaluate

∴

I a(lg) = \frac{11.95}{1.5}

Next Step Evaluate

∴

I a(lg) = 7.96666666666667A

LAST Step Rounding Answer

∴

I a(lg) = 7.9667A

A-Phase Current using A-Phase Voltage(LGF) Formula Elements

Variables

A-Phase Current LG

A-phase Current LG is the current that flows into the a-phase in open conductor fault.

Symbol: I_a(lg)

Measurement: Electric CurrentUnit: A

Note: Value can be positive or negative.

Formulas to find A-Phase Current LG

A Phase Voltage LG

A phase voltage LG is the voltage of a-phase in open conductor fault.

Symbol: V_a(lg)

Measurement: Electric PotentialUnit: V

Note: Value should be greater than 0.

Formulas to find A Phase Voltage LG

Fault Impedance LG

Fault Impedance LG is a measure of the resistance and reactance in an electrical circuit that is used to calculate the fault current that flows through the circuit in the event of a fault.

Symbol: Z_f(lg)

Measurement: Electric ResistanceUnit: Ω

Note: Value should be greater than 0.

Formulas to find Fault Impedance LG

Other Formulas to find A-Phase Current LG

Go A-Phase Current using Positive Sequence Current (LGF)

I a(lg) = I 1(lg) \cdot 3

Go A-Phase Current using Negative Sequence Current (LGF)

I a(lg) = 3 \cdot I 2(lg)

Go A-Phase Current using Zero Sequence Current (LGF)

I a(lg) = I 0(lg) \cdot 3

Go A-Phase Current using Fault Impedance(LGF)

I a(lg) = \frac{3 \cdot V 0(lg) - V b(lg) - V c(lg)}{Z f(lg)}

Other formulas in Current category

Go Positive Sequence Current using Fault Impedance(LGF)

I 1(lg) = \frac{V 1(lg) + V 2(lg) + V 0(lg)}{3 \cdot Z f(lg)}

Go Positive Sequence Current using A-Phase Current (LGF)

I 1(lg) = \frac{I a(lg)}{3}

Go Negative Sequence Current using A-Phase Current (LGF)

I 2(lg) = \frac{I a(lg)}{3}

Go Zero Sequence Current using A-Phase Current (LGF)

I 0(lg) = \frac{I a(lg)}{3}

How to Evaluate A-Phase Current using A-Phase Voltage(LGF)?

A-Phase Current using A-Phase Voltage(LGF) evaluator uses A-Phase Current LG = A Phase Voltage LG/Fault Impedance LG to evaluate the A-Phase Current LG, The a-phase Current using a-phase voltage(LGF) formula is defined as the current through any one component comprising a three-phase source or load. here we have taken the a-phase. A-Phase Current LG is denoted by I_a(lg) symbol.

How to evaluate A-Phase Current using A-Phase Voltage(LGF) using this online evaluator? To use this online evaluator for A-Phase Current using A-Phase Voltage(LGF), enter A Phase Voltage LG (V_a(lg)) & Fault Impedance LG (Z_f(lg)) and hit the calculate button.

FAQs on A-Phase Current using A-Phase Voltage(LGF)

What is the formula to find A-Phase Current using A-Phase Voltage(LGF)?

The formula of A-Phase Current using A-Phase Voltage(LGF) is expressed as A-Phase Current LG = A Phase Voltage LG/Fault Impedance LG. Here is an example- 7.966667 = 11.95/1.5.

How to calculate A-Phase Current using A-Phase Voltage(LGF)?

With A Phase Voltage LG (V_a(lg)) & Fault Impedance LG (Z_f(lg)) we can find A-Phase Current using A-Phase Voltage(LGF) using the formula - A-Phase Current LG = A Phase Voltage LG/Fault Impedance LG.

What are the other ways to Calculate A-Phase Current LG?

Here are the different ways to Calculate A-Phase Current LG-

A-Phase Current LG=Positive Sequence Current LG*3
A-Phase Current LG=3*Negative Sequence Current LG
A-Phase Current LG=Zero Sequence Current LG*3

Can the A-Phase Current using A-Phase Voltage(LGF) be negative?

Yes, the A-Phase Current using A-Phase Voltage(LGF), measured in Electric Current can be negative.

Which unit is used to measure A-Phase Current using A-Phase Voltage(LGF)?

A-Phase Current using A-Phase Voltage(LGF) is usually measured using the Ampere[A] for Electric Current. Milliampere[A], Microampere[A], Centiampere[A] are the few other units in which A-Phase Current using A-Phase Voltage(LGF) can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit